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A uniform metre rule of weight 1.0 N balances on a pivot at its 50 cm mark. A 0.60 N weight hangs at its 20 cm mark. (a) Give one everyday example of the turning effect of a force. (b) Where must a 0.90 N weight hang on the other side to balance the rule? Give the centimetre mark. (c) Calculate the upward force of the pivot on the balanced rule. (d) State the two conditions for the rule to be in equilibrium. (e) Supplement. A 0.15 N weight is then hung at the 90 cm mark, with the 0.90 N weight still in place. To which mark must the 0.60 N weight be moved to balance the rule again? (f) Supplement. Explain how your readings from (b) and (e) show that there is no resultant moment on the balanced rule.
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Cambridge IGCSE Physics 0625 · 2026–2028 v2 · Original learning materials.
The moment of a force as a measure of its turning effect, with everyday examples (1.5.2.1); moment = force × perpendicular distance from the pivot (1.5.2.2); the principle of moments with one force each side of the pivot, including balancing a beam (1.5.2.3); no resultant force and no resultant moment means equilibrium (1.5.2.4); Supplement: the principle of moments with more than one force each side (1.5.2.5) and an experiment to show there is no resultant moment on an object in equilibrium (1.5.2.6); centre of gravity (1.5.3.1), finding it for an irregular plane lamina (1.5.3.2) and its effect on stability (1.5.3.3). Couples, torque by name, forces at an angle and levers as machines are not used. Resultant forces are in Resultant force, momentum in Momentum and collisions, and pressure in Pressure.
Apparatus, amounts and times in the experiment are illustrative. Real practical work follows a teacher-approved safety method.
Official Cambridge syllabus