Pupil sheet · Stretching springs
Stretching springs — return questions
Name ______________________ Date ____________
Use one to two weeks after the lessons. Keep the notes and the lesson closed.
1. state / identify / determine / describe / explain
Answer from memory. (a) Apart from its motion, state what a force can change about an object. (b) A pupil’s results for a spring are in the table. One reading is anomalous. Identify it, and determine the extension it should have been. (c) Describe how she should draw the line on her load–extension graph. (d) Explain why you read the pointer with your eye level with it.
| load / N | extension / cm |
|---|---|
| 0 | 0 |
| 0.5 | 1.7 |
| 1.0 | 3.4 |
| 1.5 | 5.9 |
| 2.0 | 6.8 |
| 2.5 | 8.5 |
(a) What a force can change
(b) The anomalous reading
(c) The line
(d) Eye level
2. define / calculate / state / determine / explain
Supplement. Answer from memory. (a) Define the spring constant. (b) A spring has a spring constant of 75 N/m. Calculate the force that stretches it by 6.4 cm, below its limit of proportionality. (c) State what the gradient of a load–extension graph, with the load up the side, tells you. (d) Define the limit of proportionality. (e) A pupil’s spring stretches by 1.3 cm for every 0.5 N, up to 3.0 N. At 3.5 N, its extension is 9.9 cm. Determine whether 3.5 N is beyond the limit of proportionality, and explain how you know.
(a) The spring constant
(b) The force
(c) The gradient
(d) The limit of proportionality
(e) Beyond the limit?