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Answers · Formulae and equations

Formulae and equations — return questions key

Check meaning, not exact wording. These are teaching points, not official Cambridge marks.

1. FR1 · Return

Model answer. (a) CO2, NH3 and CaCO3. (b) SO3. The molecular formula gives the number and type of different atoms in one molecule: one sulfur atom and three oxygen atoms. (c) 6, 12 and 6 all divide by 6, giving CH2O. (d) Mg2+ carries +2, so it needs two NO3−; the nitrate group stays in a bracket: Mg(NO3)2.

A full answer includes

  • (a) CO2, NH3, CaCO3.
  • (b) SO3: the number and type of atoms in one molecule, 1 sulfur and 3 oxygen.
  • (c) CH2O.
  • (d) Mg(NO3)2.

Also accept

  • (a) CO2, NH3, CaCO3. (b) SO3; atoms in one molecule. (c) CH2O. (d) Mg(NO3)2.

Watch for

  • “Ammonia is NH4.” — NH4+ is the ammonium ion; ammonia is NH3.
  • “The empirical formula is always the molecular formula halved.” — Divide by the largest number that goes into every subscript; it may be 2, 3, 6 or none at all.
  • “One positive ion always joins one negative ion.” — Take just enough ions for the charges to add up to zero: Mg2+ needs two Cl−.

2. FR2 · Return

Model answer. Oxygen: both 2 and 3 go into 6, so 3O2 and 2Al2O3. That makes 2 × 2 = 4 aluminium atoms on the right, so 4Al: 4Al + 3O2 → 2Al2O3.

Lowest whole-number coefficients: 4Al(s) + 3O2(g) → 2Al2O3(s)

A full answer includes

  • 4Al + 3O2 → 2Al2O3.

Also accept

  • 4, 3, 2.

Watch for

  • “Change a small number in a formula to make the atoms balance.” — Changing a subscript makes a different substance. Balance with numbers in front of the formulae.
  • “Any numbers that balance are fine.” — Use the smallest whole numbers: if every number can be halved, halve them.

3. FR3 · Return

Model answer. (a) The sulfate ions stay dissolved on both sides, so they are spectators: Mg(s) + Cu2+(aq) → Mg2+(aq) + Cu(s). The charge is +2 on each side. (b) Oxygen comes as O2, so two CaO are made, which need two calcium atoms. Calcium is a solid metal, oxygen a gas and calcium oxide a solid: 2Ca(s) + O2(g) → 2CaO(s).

A full answer includes

  • (a) Mg(s) + Cu2+(aq) → Mg2+(aq) + Cu(s).
  • (b) 2Ca(s) + O2(g) → 2CaO(s).

Also accept

  • (a) Mg(s) + Cu2+(aq) → Mg2+(aq) + Cu(s). (b) 2Ca(s) + O2(g) → 2CaO(s).

Watch for

  • “Keep every ion in the ionic equation.” — Ions that are the same on both sides are spectator ions; leave them out.
  • “Oxygen, hydrogen, nitrogen and chlorine are written as single atoms, O, H, N and Cl.” — These elements exist as molecules of two atoms, so they are written O2, H2, N2 and Cl2.